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7p^2-29p+24=0
a = 7; b = -29; c = +24;
Δ = b2-4ac
Δ = -292-4·7·24
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-13}{2*7}=\frac{16}{14} =1+1/7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+13}{2*7}=\frac{42}{14} =3 $
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